36y^2+13y-14=0

Solution for 36y^2+13y-14=0 equation:

36y^2+13y-14=0

a = 36; b = 13; c = -14;
Δ = b2-4ac
Δ = 132-4·36·(-14)
Δ = 2185
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{2185}}{2*36}=\frac{-13-\sqrt{2185}}{72}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{2185}}{2*36}=\frac{-13+\sqrt{2185}}{72}
$